c^2+4c+4=9

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Solution for c^2+4c+4=9 equation:


Simplifying
c2 + 4c + 4 = 9

Reorder the terms:
4 + 4c + c2 = 9

Solving
4 + 4c + c2 = 9

Solving for variable 'c'.

Reorder the terms:
4 + -9 + 4c + c2 = 9 + -9

Combine like terms: 4 + -9 = -5
-5 + 4c + c2 = 9 + -9

Combine like terms: 9 + -9 = 0
-5 + 4c + c2 = 0

Factor a trinomial.
(-5 + -1c)(1 + -1c) = 0

Subproblem 1

Set the factor '(-5 + -1c)' equal to zero and attempt to solve: Simplifying -5 + -1c = 0 Solving -5 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -1c = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -1c = 0 + 5 -1c = 0 + 5 Combine like terms: 0 + 5 = 5 -1c = 5 Divide each side by '-1'. c = -5 Simplifying c = -5

Subproblem 2

Set the factor '(1 + -1c)' equal to zero and attempt to solve: Simplifying 1 + -1c = 0 Solving 1 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1c = 0 + -1 -1c = 0 + -1 Combine like terms: 0 + -1 = -1 -1c = -1 Divide each side by '-1'. c = 1 Simplifying c = 1

Solution

c = {-5, 1}

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